Home > Uncategorized > A Straight Line Through a Circle

A Straight Line Through a Circle

November 19, 2011 Leave a comment Go to comments

To find the coordinates where a straight line passes through a circle in four steps.

First: Get the straight line and circle equations.

Second: Replace the “y” variable in the circle equation with the straight line (remember to move r^2 to the other side of the equals sign).
y=mx+c and (x-a)^2+(y-b)^2=r^2
(x-a)^2+(mx+c-b)^2=r^2

Third: Multiply out and factorise.
The factorised equation will give you one or two “x” values. These values are the x coordinates of where the line intercepts the circle.

Fourth: To find the corresponding y coordinate(s), plug the “x” value(s) into the original straight line equation.

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Categories: Uncategorized
  1. March 26, 2012 at 7:46 am

    Y = X + P
    Find Y

    X(beer) P(amount of beer)

    X is directly proportionate to P thus leaving Y a variable. I have deduced that Y is the babalas factor.

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